1513-number-of-substrings-with-only-1s
DevGod needs to write a blog entry for this problem!
/**
* @param {string} s
* @return {number}
*/
var numSub = function(s) {
let count = 0;
let ans = 0
for(let I = 0; I<s.length; I++){
if(s[I] === "1"){
count++;
}else{
ans += (count*(count+1))/2;
count = 0;
}
}
ans += (count*(count+1))/2;
count = 0;
return ans% (10**9 + 7);
};