3016-minimum-number-of-pushes-to-type-word-ii

DevGod

Vtuber

Caution

DevGod needs to write an editorial for this problem!

js

/**
 * @param {string} word
 * @return {number}
 */
var minimumPushes = function(word) {
    let score = 0;
    let freqMap = _.orderBy(_.countBy(word), [], ['desc']);
    _.forEach(freqMap, (value, key) => score += value*(Math.floor(key/8)+1));
    return score;
};

py

class Solution:
    def minimumPushes(self, word: str) -> int:
        myCounter = Counter(word).most_common()

        score = 0
        for i, (key, val) in enumerate(myCounter):
            score += val * (int(i / 8) + 1)

        return score